How to compare two characters in Java in if conditon?

Question

How can I compare two characters in Java?

while(s1.hasNext()) {
    if(a[j].equals('x')
        x++;
    if(a[j].equals('y')
        y++;
}

I have repeated the loop using for loop for n times and a[j] is an array. I am getting the error at if condition inside the while loop. Could anyone please explain me about the error?

Bracket not closed properly if(a[j].equals('x')) – Thirumal Aug 06 '16 at 03:36 — Thirumal, Aug 06 '16 at 03:36
char cannot be dereferenced..at the if condition line – Chaitanya Aug 06 '16 at 04:02 — Chaitanya, Aug 06 '16 at 04:02

score 0 · Answer 1 · answered Aug 06 '16 at 03:40

0

you can also compare characters using == as following:

while(s1.hasNext())
{
    if(a[j] == 'x')
    x++;
    if(a[j]=='y')
    y++;
}

here array a should be a character array.

If a is a string than you have to use s.charAt(int index) to get desired character, as following:

while(s1.hasNext())
{
    if(a.charAt(j) == 'x')
    x++;
    if(a.charAt(j) == 'y')
    y++;
}

answered Aug 06 '16 at 03:40

Kaushal28

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a is not a string it is an character array.. and also i have written what you said but getting the same errors at the if condition only.. – Chaitanya Aug 06 '16 at 03:57
what is error??@Ch_03 – Kaushal28 Aug 06 '16 at 03:58
error: cannot find symbol if(a.charAt(j) == 'x') symbol: method charAt(int) location: variable a of type char[] – Chaitanya Aug 06 '16 at 04:00
I said if `a` is string than use `a.charAt()`. If it is an array than use my 1st snippet. @Ch_03 – Kaushal28 Aug 06 '16 at 04:01
the first snippet i had tried already but if has not been worked..because there are no compilation errors but i haven't got the output.. – Chaitanya Aug 06 '16 at 04:05
post your whole code@Ch_03 – Kaushal28 Aug 06 '16 at 04:09
@Ch_03 if your array of character type then u have use like the first snippet – mss Dec 30 '19 at 09:27

How to compare two characters in Java in if conditon?

1 Answers1