I have an array like this
int[] intnumber = new int[]{10,25,12,36,100,54,68,75,63,24,1,6,9,5};
I want to find the greatest number and make it In order from largest to smallest
like this 100,75,68,63,54,36,25,24,12,10,9,6,5,1
I have an array like this
int[] intnumber = new int[]{10,25,12,36,100,54,68,75,63,24,1,6,9,5};
I want to find the greatest number and make it In order from largest to smallest
like this 100,75,68,63,54,36,25,24,12,10,9,6,5,1
int[] intnumber = new int[] { 10, 25, 12, 36, 100, 54, 68, 75, 63, 24, 1, 6, 9, 5 };
int maxValue = intnumber.Max();
You can sort the array for viewing elements in ascending order
Array.Sort(intnumber);
Array.Reverse(intnumber);
foreach (var str in intnumber )
{
MessageBox.Show(str.ToString());
}
exactly output that you want.
int[] intnumber = new int[] { 10,25,12,36,100,54,68,75,63,24,1,6,9,5 };
Array.Sort<int>(intnumber ,
new Comparison<int>(
(i1, i2) => i2.CompareTo(i1)
));
intnumber .Dump();
P.S. To run this demo you need to follow these steps:
1.Download LINQPad.
2.Download the demo file, open it with LINQPad and hit F5.
You can use :
int[] intnumber = new int[]{10,25,12,36,100,54,68,75,63,24,1,6,9,5};
Array.Sort(intnumber );
Array.Reverse(intnumber );
int max = intnumber[0];
Try this,
int[] intnumber = new int[] { 10, 25, 12, 36, 100, 54, 68, 75, 63, 24, 1, 6, 9, 5 };
//Maximum Value
int maxValue = intnumber.Max();
//Maximum Index
int maxIndex = intnumber.ToList().IndexOf(maxValue);
I found my answer with your helps
Console.WriteLine("How many Numbers Do you want? ");
int counter = int.Parse(Console.ReadLine());
double[] numbers = new double[counter];
for (int i = 0; i < numbers.Length; i++)
{
Console.Write((i + 1) + " : ");
numbers[i] = Convert.ToDouble(Console.ReadLine());
}
Console.WriteLine("_______________________________________________");
Array.Sort(numbers);
Array.Reverse(numbers);
foreach (double item in numbers)
{
Console.WriteLine(item);
}
Console.WriteLine("_______________________________________________");
Console.WriteLine("The Greatest Number is " + numbers[0]);
Console.ReadKey();
Let intNumbers
be the array that you are using, Then you can use the .Max()
method of the Array Class to get the maximum value, that is the greatest number. If you want to Sort the Current array means You have to use the .Sort()
method. The requirement is simply Printing the Array in descending order means you have to use the .OrderBy()
int[] inputNumbers = new int[] { 15, 12, 11, 23, 45, 21, 2, 6, 85, 1 };
Console.WriteLine("Input Array is : {0}\n",String.Join(",",inputNumbers.OrderByDescending(x=>x)));
Console.WriteLine("Max value in the array is : {0}\n",inputNumbers.Max());
Console.WriteLine("Array in descending order : {0}\n",String.Join(",",inputNumbers.OrderByDescending(x=>x)));
Here is a working Example
int max = Integer.MIN_VALUE;
for (int i =0; i < intnumber.length; i++)
{
int num = intnumber[i];
//Check to see if num > max. If yes, then max = num.
}
System.out.println(max);