How to run an executable on all files in a directory matching a file extension wildcard pattern?

Question

I have a file testfile.exe that runs with parameters like below:

testfile.exe c:\path1\file.txt 3 c:\path2\file2.txt

The second parameter 3 is a sampling factor.

So I run the application with the parameters:

input file with path
a sampling factor
output file with path

What would be needed in a batch file to search in a source directory for all files with a specific file extension and run the command with the input/sample/output parameters?

This might help you! http://stackoverflow.com/questions/138497/iterate-all-files-in-a-directory-using-a-for-loop — SilverSurfer, Aug 15 '16 at 15:16

score 0 · Answer 1 · edited Aug 16 '16 at 11:23

0

This worked:

set "SourceFolder=c:\path1"
set "OutputFolder=c:\path2"
set "SampleFactor=1"
for %%a in ("%SourceFolder%\*.ext") do (
    example.exe "%%a" "%SampleFactor%" "%OutputFolder%\%%~na.ext"
)

edited Aug 16 '16 at 11:23

Mofi

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answered Aug 15 '16 at 16:16

mgdicom

3
4

All file/folder names without or with path containing a space or one of the characters ``&()[]{}^=;!'+,`~`` must be enclosed in double quotes. Open a command prompt window, enter `cmd /?` and read the output help pages where on last paragraph on last help page you can read about this list. I modified your not working code to the working code above. – Mofi Aug 16 '16 at 11:26

How to run an executable on all files in a directory matching a file extension wildcard pattern?

1 Answers1