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My android app has a Button widget, wherein I have written the following inside the file activity_main.xml, apart from other necessary text. 

<Button
   android:layout_width="wrap_content"
   android:layout_height="wrap_content"
   android:text="Numbers"
   android:id="@+id/btnBrowse"
   android:onClick="clickButtonBrowse"
 />

In the file MainActivity.java apart from the other functions, I wrote the following: 

protected void clickButtonBrowse() {
    Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
    intent.addCategory(Intent.CATEGORY_OPENABLE);
    intent.setType("text/plain");
    startActivity(intent, FILE_REQUEST_CODE);
}

My idea is to open a file browser, and select a file. I have taken the help from this question on selecting a file.

Now I have no idea on the following:

  1. How to get the name of the file from the intent, so that I can read it.
  2. How is this FILE_REQUEST_CODE to be defined? What are the permissible values?

Could you help me?

Community
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Indian
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1 Answers1

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You need to startActivityForResult not startActivity, as in the example you were using.
Then you can:

public synchronized void onActivityResult(final int requestCode,
        int resultCode, final Intent data) {

    if (resultCode == Activity.RESULT_OK) {
        String filePath = data.getStringExtra(FileDialog.RESULT_PATH);
    } 
}
Hossein
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usajnf
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  • Where is FileDialog ?? – Indian Aug 17 '16 at 13:26
  • It is whatever activity you are using to browse the files. See the details in the link you posted. It tells you how to get a file. Whatever you name your copy of that class, substitute for FileDialiog – usajnf Aug 17 '16 at 14:09