python 3.6, for input() - achieve time out and skip to next line

Asked Aug 17 '16 at 18:30

Active Aug 17 '16 at 19:00

Viewed 88 times

Newbie to python.

I looked around the web and found raw_input() had some workaround to achieve timeout. But in 3.6 there is no raw_input()

 name1 = str(input("please enter name of preferred student 1: "))
 name2 = str(input("please enter name of preferred student 2: "))

I want user to enter input for first line in 5 secs, if he dint enter any input i want my code to skip for second line of code.

edited Aug 17 '16 at 19:00

asked Aug 17 '16 at 18:30

Sachinlionel

Am newbie i dint understand much in that, not sure of duplicate. – Sachinlionel Aug 17 '16 at 18:37
Am trying timeout with input() function, not print("") – Sachinlionel Aug 17 '16 at 18:57
The duplicate question explains *exactly* what you're trying to do, the first answer is most applicable. Create a signal and a handler that raises an Exception; wrap timed code in try-except to catch aforementioned exception. – Dimitris Fasarakis Hilliard Aug 18 '16 at 00:16

0 Answers0