Regex required: To return substring which is present after first completion of parentheses

Question

Example- 1)(abc)xxx --> output-xxx

2)(abc)(xxx) --> output-xxx

3)((abc)xxx) ---> output-xxx

4)((abc) xxx + yyy)--> output-xxx+yyy

5)((abc)) ---> output-null

You can't count balanced parentheses with a regexp. You'll need to use something else. — The Archetypal Paul, Oct 11 '10 at 10:08
This isn't exactly a duplicate, but it has the same answer: http://stackoverflow.com/questions/3903965/regex-required-it-should-match-for-following-patterns — Greg Hewgill, Oct 11 '10 at 10:09
True. http://www.texttoolkit.com/index.php?option=com_content&view=article&id=63:parsing-balanced-parenthesis-with-regular-expressions&catid=35:technology&Itemid=55 — Thilo, Oct 11 '10 at 10:11

score 0 · Answer 1 · answered Oct 11 '10 at 10:16

0

This actually does what you ask for for all your examples, but I suspect is not what you wanted

[^\)]+\)[\(]*([^\)]*)

answered Oct 11 '10 at 10:16

1 Answers1