Find the next highest number in array

Question

I have an array of numbers and a value. I'd like to find the numbers around the value. The most important is the highest value but I need both.

var array = [2,4,5,8,11];
var value = 9;

The result I need should be : 8 and 11.

How can I do that?

Thanks.

I didn't find a solution to my problem, that's why I ask. I did it when datas in array are always incrementing by 1. But for my question, I didn't find a solution. And I'm trying to do that in jQuery. — PSport, Aug 22 '16 at 15:00
It seems you don't understand the purpose of Stack Overflow or jQuery... — Alexander O'Mara, Aug 22 '16 at 15:01
I suggest you start by learning how to write for-loops and comparisons in Javascript, and leave jquery aside. There are numerous sites and books devoted to teaching Javascript. — Griffin, Aug 22 '16 at 15:01
@PSport: you can tweak this answer to get both solutions http://stackoverflow.com/a/19277804/1719752 — Milind Anantwar, Aug 22 '16 at 15:02

score 4 · Answer 1 · answered Aug 22 '16 at 15:05

Just write a simple for-loop searching for each of the values.

So for example:

function findNumbers(arr, num){
    var low = num + 1; //largest number lower than num, set initial value above num
    var high = num - 1; //smallest number higher than num, set initial value below num
    for(var i = 0; i < arr.length; i ++){
         if(arr[i] > low && arr[i] < num){
             low = arr[i];
         }
         if(arr[i] < high && arr[i] > num){
             high = arr[i];
         }
    }

    //optional check to see if low/high exists
    if(low > num){
        low = -1; //not found
    }
    if(high < num){
        high = -1; //not found
    }
    return [low,high];

}

and there you go. This works whether or not arr is sorted.

Ehsan · Accepted Answer · 2016-08-22T15:13:35.530

This help you :

<!DOCTYPE html>
<html>
<head>
</head>
<body>
    <script>
        
        var array = [2,4,5,8,11];
        
        var value = 9;
        
        var min,max;
        
        fun();
        
        function fun() {
            
            var sortArray = array.sort(function(a,b){return a-b});
            
            for(var i=0; i<sortArray.length;i++) {
                
                if (sortArray[i] < value)
                    min = sortArray[i];
                
                if (sortArray[i] > value)
                    max = sortArray[i];
            }
            
            alert(min + " , " + max);
        }
        
    </script>
</body>
</html>

Exactly what I needed thanks. I can use it and adapt it perfectly to my need. — PSport, Aug 22 '16 at 15:13

score 1 · Answer 3 · answered Aug 22 '16 at 15:12

Looking at your question looks like you are still learning jquery.However I am sure you will get good suggestions here.

Here is an example with your test case,I am leaving the explanation on you so that you can study each line and learn.

var myArray = [2, 4, 5, 8, 11];
var myValue = 9;

function BiggerThan(inArray) {
  return inArray > myValue;
}

function LesserThan(inArray) {
  return inArray < myValue;
}    

var arrBiggerElements = myArray.filter(BiggerThan);
var nextElement = Math.min.apply(null, arrBiggerElements);
alert(nextElement);

var arrLesserElements = myArray.filter(LesserThan);
var prevElement = Math.max.apply(null, arrLesserElements);
alert(prevElement);

Ok thank you, I'm going to analyse that. – PSport Aug 22 '16 at 15:14 — PSport, Aug 22 '16 at 15:14

Find the next highest number in array

3 Answers3