How can my JAR open itself as a stream?

Question

I'm trying to open a JAR as a stream, but can't understand where to get this stream...

JarInputStream s = new JarInputStream(/* what is here? */);

Where to get this stream? I'm trying to open the JAR which is currently is in charge.

possible duplicate of [List files inside a jar ](http://stackoverflow.com/questions/1429172/list-files-inside-a-jar) — erickson, Oct 12 '10 at 13:43

score 4 · Accepted Answer · edited May 23 '17 at 11:55

4

From my answer to a similar question:

CodeSource src = MyClass.class.getProtectionDomain().getCodeSource();
if (src != null) {
  URL jar = src.getLocation();
  ZipInputStream zip = new ZipInputStream(jar.openStream());
  /* Now examine the ZIP file entries to find those you care about. */
  ...
} 
else {
  /* Fail... */
}

edited May 23 '17 at 11:55

Community

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answered Oct 12 '10 at 13:44

erickson

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score 2 · Answer 2 · answered Oct 12 '10 at 13:43

Look up a class that is in the JAR. Eg:

Class clazz = SomeClass.class;
URL resource = clazz.getResource(clazz.getSimpleName()+".class");
JarFile jarFile = ((JarURLConnection)resource.openConnection()).getJarFile();

I know you wanted a JarInputStream but I would bet JarFile does what you want.

How can my JAR open itself as a stream?

2 Answers2