Are variables case-sensitive in exprtk?

Question

When I define an expression in my exprtk string, like

var x := sqrt(y);

and I try to add another variable

var X := 2*z;

do I get a conflict? Thanks in advance.

Why use the C++ tag? The syntax you presented is not valid for C++. — Thomas Matthews, Aug 26 '16 at 14:57
Thomas: because exprtk is a C++ library. Robert: I just tested it here, and I get a conflict. Should I remove the question? — Lucio Carlos Pimentel Paiva, Aug 26 '16 at 15:00
@LucioCarlosPimentelPaiva just answer your question yourself if you have found the answer, — Peter K, Aug 26 '16 at 15:01
I don't know if it's expected or not. But it gave me a headache for hours when I tried to debug my code. — Lucio Carlos Pimentel Paiva, Aug 26 '16 at 15:05

score 9 · Accepted Answer · answered May 29 '17 at 23:40

9

As of March 2017, the author of exprtk has added support for case sensitive variables: https://github.com/ArashPartow/exprtk/blob/master/readme.txt#L4477

Just include #define exprtk_disable_caseinsensitivity and you are good to go!

answered May 29 '17 at 23:40

1

Nice! It didn't exist when I posted the question, it's good to know that it is supported now. Thanks – Lucio Carlos Pimentel Paiva Jun 09 '17 at 18:50

score 8 · Answer 2 · answered Aug 26 '16 at 15:03

8

I just found the answer: variables defined within exprtk expressions are NOT case sensitive. In the example above you will get a conflict.

answered Aug 26 '16 at 15:03

2 Answers2