I use java to excute a command line to create a database, i get an error when i excute this piece of code:
private final String POSTGRES_PATH = "\"C:\\Program Files\\PostgreSQL\\9.3\\bin\\psql.exe\"";
private final String DATA_BASE = "bd_name";
private void creerDataBase() {
String command = this.POSTGRES_PATH + " -U postgres -d postgres -c \"CREATE DATABASE " + this.DATA_BASE + "\"";
System.out.println("command = " + command);
String creerBDD = executerCommande(command);
System.out.println("Resultat : " + creerBDD);
}
public String executerCommande(String command) {
String line;
String resultat = "";
try {
ProcessBuilder builder = new ProcessBuilder("cmd.exe", "/c", command);
builder.redirectErrorStream(true);
Process p = builder.start();
BufferedReader r = new BufferedReader(new InputStreamReader(p.getInputStream()));
while (true) {
line = r.readLine();
if (line == null) {
break;
}
resultat += line + "\n";
}
} catch (Exception e) {
System.out.println("Exception = " + e.getMessage());
}
return resultat;
}
I get this result:
command = "C:\Program Files PostgreSQL\9.3\bin\psql.exe"\ -U postgres -d postgres -c "CREATE DATABASE bd_name"
and this error:
'C:\Program' n'est pas reconnu en tant que commande interne
This mean that Program is not an intern command.
but when i excute this command in CMD it work fine?
Is there any way to Build this Path because the ProcessBuilder not recognize C:\Program Files