I'm trying to set up a pyqt signal between a block of UI code and a separate python class that is just for handling event responses. I don't want to give the UI code access to the handler (classic MVC style). Unfortunately, I am having difficulty connecting the slot to the signal. Here is the code:
from PyQt5 import QtCore
from PyQt5.QtCore import QObject
class UiClass(QObject):
mySignal = QtCore.pyqtSignal( str )
def __init__(self):
QObject.__init__(self)
def send_signal(self):
self.mySignal.emit("Hello world!")
class HandlerClass():
currentMessage = "none"
def register(self, mySignal):
mySignal.connect(self.receive_signal)
@QtCore.pyqtSlot(str)
def receive_signal(self, message):
self.currentMessage = message
print(message)
ui = UiClass()
handler = HandlerClass()
handler.register(ui.mySignal)
ui.send_signal()
When I run this code it fails at the handler.register line. Here is the error:
Traceback (most recent call last):
File "C:\git\IonControl\testpyqtslot.py", line 25, in
handler.register(ui.mySignal)
File "C:\git\IonControl\testpyqtslot.py", line 17, in register
mySignal.connect(self.receive_signal)
TypeError: connect() failed between UiClass.mySignal[str] and receive_signal()
I'd like this code to successfully register the signal to the slot and have the handler print "hello world" at the end. What did I do wrong here?
My basic question is this: how do I connect a signal to a slot function that is part of a class?