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Now I have a file named Land/SeaMask and I want to open it, but it cannot be recognized as a filename by programme, but as a directory, how to do it?

Jiao Li
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  • Show us your code and error you received. – DeepSpace Aug 30 '16 at 09:36
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    Possible duplicate of [How do I escape forward slashes in python, so that open() sees my file as a filename to write, instead of a filepath to read?](http://stackoverflow.com/questions/29014481/how-do-i-escape-forward-slashes-in-python-so-that-open-sees-my-file-as-a-file) – Daniel Aug 30 '16 at 09:37
  • For a full discussion of this problem, see [this](http://stackoverflow.com/questions/9847288/is-it-possible-to-use-in-a-filename). – goldiex Aug 30 '16 at 09:40
  • try `Land\\seamask` – Daniel Lee Aug 30 '16 at 09:59

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First of all I recommend you to find out how Python interpreter displays yours file name. You can do this simply using os built-in module: 

import os
os.listdir('path/to/directory')

You'll get a list of directories and files in directory you passed as argument in listdir method. In this list you can find something like Land:SeaMask. After recognizing this, open('path/to/Land:SeaMask') will work for you.

finomayato
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