Rspec Array match partial string timestamp

Question

I have a array like this:

["xxxxxxxxx", 448, "2016-08-29", 1, "Trading", 53, "Trading", 2016-06-03 00:00:00 -0500, 2016-06-03 00:00:00 -0500, "RBS", "USD", "United States Dollar", nil, 2016-10-08 00:00:00 -0500, 2016-09-08 00:00:00 -0500, "2016-09-08 00:00:00 -0500","lcz076", nil, 5, 2016-10-08 00:00:00 -0500, 2016-09-08 00:00:00 -0500, "9", 448, "P", nil]

And I need to match a value for this value only "2016-09-08 00:00:00"

How do I do that?

Do you just want to check if it is inside? then use `.include?` — Muntasir Alam, Aug 30 '16 at 14:31

score 0 · Answer 1 · answered Aug 30 '16 at 14:40

0

First convert all the dates into Strings

Then after set it to a variable a

a = ["xxxxxxxxx", 448, "2016-08-29", 1, "Trading", 53, "Trading", "2016-06-03 00:00:00 -0500, 2016-06-03 00:00:00 -0500"...

I noticed all of the dates of the type you wanted to check have -0500 so you can take out that part by looping in the array with this

new_str[i] = str.slice(0..(str.index('-0500')))

Now you can just use .include?("stuff here")

answered Aug 30 '16 at 14:40

Muntasir Alam

1,777
2
17
26

Its always Last 5 digits so how do you slice that last 5 instead – Kiul Logoto Aug 30 '16 at 15:22
See this http://stackoverflow.com/questions/4486709/how-do-i-remove-substring-after-a-certain-character-in-a-string-using-ruby, you will learn alot. – Muntasir Alam Aug 30 '16 at 15:29

score 0 · Answer 2 · answered Aug 30 '16 at 15:27

Assuming you have:

a = ["xxxxxxxxx", 448, "2016-08-29", 1, "Trading", 53, "Trading", "2016-06-03 00:00:00 -0500", "2016-06-03 00:00:00 -0500", "RBS", "USD", "United States Dollar", nil, "2016-10-08 00:00:00 -0500", "2016-09-08 00:00:00 -0500", "2016-09-08 00:00:00 -0500", "lcz076", nil, 5, "2016-10-08 00:00:00 -0500", "2016-09-08 00:00:00 -0500", "9", 448, "P", nil]

RSpec expectation should be:

matches = a.select{ |x| x.to_s.match("2016-09-08 00:00:00") }
expect(matches).not_to be_empty

Rspec Array match partial string timestamp

2 Answers2