"Unexpected token o" in JSON

Question

I have an android app where I'm trying to send data from editText to server. I'm trying to pack data to JSON:

editTextLogin = (EditText) findViewById(R.id.editTextLogin);
editTextPass = (EditText) findViewById(R.id.editTextPass);
JSONObject logPass = new JSONObject();
try {
    logPass.put("login", editTextLogin.getText().toString());
    logPass.put("pass", editTextPass.getText().toString());
} catch (JSONException e) {
    e.printStackTrace();
}
mSocket.emit("logPass", logPass);

After that I receive these data on server and try to parse it to JS object:

socket.on('logPass', function(dataJSON) {
    console.log(dataJSON.admin);
    data = JSON.parse(dataJSON);
});

I can print dataJSON, it is: ( login: 'admin', pass: '1234' ) but when I'm trying to parse it I have error: Unexpected token o

What's it and how to solve it?

Possible duplicate of [Parsing JSON giving "unexpected token o" error](http://stackoverflow.com/questions/15617164/parsing-json-giving-unexpected-token-o-error) — Nikhil, Sep 01 '16 at 04:58
I don't understand. You are accessing `dataJSON.admin` but are trying to parse `dataJSON` as JSON? You can only pass a **string** to `JSON.parse`. If accessing `dataJSON.admin` is successful then clearly `dataJSON` is not a string containing JSON. — Felix Kling, Sep 01 '16 at 05:01
@levshkatov - don't try to parse something unless it is a valid JSON string - a javascript **Object** is not a **String** — Jaromanda X, Sep 01 '16 at 05:01
copy your JSON and check it on jsonlint.com then it will verify ok then only parse — black_pottery_beauty, Sep 01 '16 at 05:02
I understand that it isn't a valid JSON. I'm asking how to make it valid in java code. What's wrong im my java code, why it creates a wrong JSON? — levshkatov, Sep 01 '16 at 05:04

black_pottery_beauty · Accepted Answer · 2016-09-01T05:29:41.843

0

import org.json.simple.JSONObject;

class JsonDemo {

   public static void main(String[] args){
      JSONObject obj = new JSONObject();

      obj.put("login", "admin");
      obj.put("pass", "admin123");

      System.out.print(obj);
   }
}

OR

import org.json.simple.JSONObject;

class JsonDemo {

   public static void main(String[] args){

      JSONObject obj = new JSONObject();

      obj.put("login","admin");
      obj.put("pass","admin123");

      StringWriter out = new StringWriter();
      obj.writeJSONString(out);

      String jsonText = out.toString();
      System.out.print(jsonText);
   }
}

OUTPUT

{"login": "admin", "pass":"admin123"}

Bug Issue

mSocket.emit("logPass", logPass.toString());

I hae tried this is working..

edited Sep 01 '16 at 05:29

answered Sep 01 '16 at 05:10

black_pottery_beauty

861
8
17

Ok, but how to do the same with editText.getText() ? – levshkatov Sep 01 '16 at 05:17
I also try simle printing values in "" like you and it works, but I need to put values from editText – levshkatov Sep 01 '16 at 05:18
@levshkatov Escape the values with `\"` for `String` representation – Shaishav Sep 01 '16 at 05:19
mSocket.emit("logPass", logPass.toString()); try this it may work – black_pottery_beauty Sep 01 '16 at 05:21
@Shaishav What do you mean? I use simple admin 1234, it doesn't have `\"` – levshkatov Sep 01 '16 at 05:22
@Console.log Thanks! It helps! – levshkatov Sep 01 '16 at 05:25
@levshkatov gd keep it up and first always try to debug the issue – black_pottery_beauty Sep 01 '16 at 05:30

"Unexpected token o" in JSON

1 Answers1