Strange Core Dump problem

Question

My this code is dumping core :

int main(int argc,char *argv[])
{
   char *p = "onnm";
   printf("%c\n",++*(p++));
   return 0;
}

What might be the reason in printf line ?

Your debugger should report what caused the core dump when you load it -- ie, is it an access violation, segmentation fault, misaligned read, etc. — Crashworks, Oct 13 '10 at 22:43
See [this question](http://stackoverflow.com/questions/2096448). — BlueRaja - Danny Pflughoeft, Oct 13 '10 at 22:45

score 3 · Answer 1 · answered Oct 13 '10 at 22:43

3

string literals are read-only, you can't change them.

Use e.g. char p[] = "onnm";

answered Oct 13 '10 at 22:43

nos

score 1 · Answer 2 · answered Oct 14 '10 at 05:26

You are able to code like this because of the "an inconsistency in the language standard" of C. e.g.,

const char const_buff[] = { 'o','n', 'n', 'm', '\0' }; // OK

char* pArray = const_buff;            // not OK

In the same line it should have not allowed you to compile,

char *p = "onnm";

But you are able to compile, so allowing you to do the the mistake of changing a read-only string.

++ * ( p++)

2 Answers2