I have a Perl program where the user enters some text, a search pattern and a replacement string.
I am using the the s///
operator to replace the search pattern by the replacement string, but in this scenario, if the user enters capture variables (like $1
) or backslash escapes (like \u
or \L
) in the replacement string, the replacement pattern should process these metacharacters but rather it is treating them as string characters.
I have the following code:
#!/usr/bin/perl -w
use strict;
chomp(my $text = <STDIN>); #read the text
chomp(my $regex = <STDIN>); #read the search pattern
chomp(my $replace = <STDIN>); #read the replacement pattern
$text=~s/$regex/$replace/g; # do replacement
print $text,"\n";
The sample input for this code is
fred flintstone and wilma flintstone are good couples
(fred|wilma) flintstone
\u\L$1\E Flintstone
The output is for above code is
\u\L$1\E Flintstone and \u\L$1\E Flintstone are good couples
I have found a way to make this correct in the following code:
#!/usr/bin/perl -w
use strict;
chomp(my $text = <STDIN>);
chomp(my $regex = <STDIN>);
chomp(my $replace = <STDIN>);
$replace = '"' . $replace . '"'; # creating the string as '"\u\L$1\E Flintstone"'
$text = ~s/$regex/$replace/gee; # applying double evaluation
print $text,"\n";
Now this code gives the correct output as
Fred Flintstone and Wilma Flintstone are good couples
I want to know if there is a better approach for this problem?