Get timestamp in seconds from python's datetime

Question

How to get timestamp from the structure datetime? What is right alternative for non-existing datetime.utcnow().timestamp()?

This answer below is much simpler than the accepted: https://stackoverflow.com/a/56689007/3559330 — mattyb, May 21 '21 at 23:20

Alex · Answer 1 · 2020-05-23T12:35:40.727

60

use time, and int to remove the milliseconds

from time import time 

int(time())

# 1561043225

edited May 23 '20 at 12:35

answered Jun 20 '19 at 15:11

Alex

score 12 · Accepted Answer · answered Sep 02 '16 at 14:06

12

import time,datetime
time.mktime(datetime.datetime.today().timetuple())

answered Sep 02 '16 at 14:06

galaxyan

1

Very cumbersome solution. As python. Many operations for such small work. C has time() and it works like a charm :) – kyb Sep 02 '16 at 14:11

score 10 · Answer 3 · edited May 23 '17 at 10:30

10

There is another stupid trick - achieve timedelta

(datetime.utcnow()-datetime(1970,1,1,0,0,0)).total_seconds()

found here. Better

(datetime.utcnow()-datetime.fromtimestamp(0)).total_seconds()

And this solution contains subseconds.

edited May 23 '17 at 10:30

Community

answered Sep 02 '16 at 15:43

kyb

score 9 · Answer 4 · answered Sep 02 '16 at 14:32

9

If you don't have to get timestamp from structure datetime, you can decrease instruction like this

import time
print time.time()

answered Sep 02 '16 at 14:32

Damotorie

This construction returns the time in seconds since the epoch as a **floating point number**, for example: `1558442772.1057804`. – Prisacari Dmitrii May 21 '19 at 12:48

score -3 · Answer 5 · answered Sep 02 '16 at 15:45

If I understand correctly what sort of output you are seeking:

from datetime import datetime
timestamp = datetime.now().strftime("%H:%M:%S")
print(timestamp)

> 11:44:40

EDIT: Appears I misinterpreted your question? You are asking for the naive universal time, then galaxyan's answer is concise.

5 Answers5