If statement causes page not to load

Question

I have a switch (checkboxes) and when $checkedans = true then flip the switch to checked else leave default (unchecked).

The error is when i try load the page it just goes white screen.

The switch and all works perfectly without the php inside but i need the if statement. Anyone know why this is happening / know a fix?

My code:

echo"
                <td class=\"alarmvalue\" style=\"padding:2px 15px;\">
                    <label class=\"switch-lightp2 well_\" onchange=\"checkSelectedScheduleType()\">";
                        if ($checkedans == true) {
                                echo "<input id=\"radioSelected\" name=\"radioSelected\" type=\"checkbox\" value=\"\" checked>\n"
                            }else{
                                echo "<input id=\"radioSelected\" name=\"radioSelected\" type=\"checkbox\" value=\"\">\n";
                            } 
                echo"   <span><span>keep</span><span>remove</span></span><a class=\"btn btn-primary\"></a>
                    </label>
                </td> "

Get rid of mixing PHP and HTML. This would be my fix for all of your dev issues ;) — B001ᛦ, Sep 02 '16 at 14:05
You're missing some semicolons and I wouldn't compare boolean values, just do `if($checkedans)` — Andrew Li, Sep 02 '16 at 14:06
Please use Netbeans or else as coding tool. Use `error_reporting(E_ALL);` at the first line of your script while developing. — JustOnUnderMillions, Sep 02 '16 at 14:09

score 0 · Accepted Answer · answered Sep 02 '16 at 14:21

0

Issue was due to a missing semicolon.

On line:

echo "<input id=\"radioSelected\" name=\"radioSelected\" type=\"checkbox\" value=\"\" checked>\n"

Should be:

echo "<input id=\"radioSelected\" name=\"radioSelected\" type=\"checkbox\" value=\"\" checked>\n";

answered Sep 02 '16 at 14:21

William

1,009
15
41

Activate error messages. – Petter Pettersson Sep 05 '16 at 13:37

If statement causes page not to load

1 Answers1