PHP core ZipArchive versus ZipStream-PHP

Question

I am checking good solutions for zipping stream content from S3, I came across to ZipStream-PHP API, which has been used by s3-bucket-stream-zip-php API however I guess with the help of core PHP class ZipArchive, and its function ZipArchive::addFromString we can achieve the same.

My query is ZipStream-PHP API is better solution then ZipArchive for zipping stream content from S3 OR any other cloud service?

If someone is down voting please add your reason in comments as well. — Sukhjinder Singh, Sep 04 '16 at 13:36
I was trying to find some help on this topic! Would be helpful if any one can suggest based on their experience!! — jas, Sep 04 '16 at 13:45
@SukhjinderSingh if the solution below answered your question, please mark it as the solution. — Forer, Mar 27 '19 at 09:27

score 3 · Answer 1 · answered Jun 23 '17 at 11:14

The best solution from my experience is to use aws-sdk-php to access objects on S3 via an s3client with registerStreamWrapper() enabled. Then use fopen to stream objects from S3 and feed that stream directly to ZipStream's addFileFromStream() function and let ZipStream take it from there. No ZipArchive, no massive memory overhead, no creating zip at server or duplicating files from S3 on the web server to subsequently use to stream a zip.

So:

//...

$s3Client->registerStreamWrapper(); //required

//test files on s3
$s3keys = array(
  "ziptestfolder/file1.txt",
  "ziptestfolder/file2.txt"
);

// Define suitable options for ZipStream Archive.
$opt = array(
             'comment' => 'test zip file.',
             'content_type' => 'application/octet-stream'
            );

//initialise zipstream with output zip filename and options.
$zip = new ZipStream\ZipStream('test.zip', $opt);

//loop keys useful for multiple files
foreach ($s3keys as $key) {

       // Get the file name in S3 key so we can save it to the zip 
       //file using the same name.
       $fileName = basename($key);

       //concatenate s3path.
       $bucket = 'bucketname';
       $s3path = "s3://" . $bucket . "/" . $key;        

       //addFileFromStream
       if ($streamRead = fopen($s3path, 'r')) {
           $zip->addFileFromStream($fileName, $streamRead);        
       } else {
           die('Could not open stream for reading');
       }
}

$zip->finish();

And if you are using ZipStream in a Symfony controller action, see this answer too: https://stackoverflow.com/a/44706446/136151

PHP core ZipArchive versus ZipStream-PHP

1 Answers1