Creating a coin flip class

Question

I have recently begun programming at university and I am a little stumped with one of my tutorial problems.

I basically need to create a method within a class which uses the Random.nextInt() method to flip a coin, assigning and saving the value once the process has been run.

MY current attempts include this:

public void Flip() {

int flipResult;

flipResult = mRandNumGen.nextInt(1);

if(flipResult == 0)
{
mFace = 'H';
}
else
{
mFace = 'T'
}

}

mFace and mRandNumGen are variables which have been declared already outside the specific method. What exactly is going wrong here? I can't for the life of me get this to work :/

So exactly what happens when you run your code? Do you get an error? — sorifiend, Sep 05 '16 at 01:00
You're missing a semicolon in the else block, and make sure you're using `char` data type. — Andrew Li, Sep 05 '16 at 01:04
the error say at cointest.Coin.Flip(Coin.java:46) and at cointest.CoinTest.main(CoinTest.java:26). Java returned:1 BUILD FAILED — Bailey Evans, Sep 05 '16 at 01:10
Can you please paste the full message, or at least mark which lines are 26 and 46 — Scary Wombat, Sep 05 '16 at 01:23

score 3 · Answer 1 · answered Sep 05 '16 at 01:30

3

Simple way to do this:

if (mRandNumGen.nextBoolean()) {
    mFace = 'H';
} else {
    mFace = 'T';
}

answered Sep 05 '16 at 01:30

Đăng Khoa Huỳnh

130
1
5

score 2 · Answer 2 · answered Sep 05 '16 at 01:01

2

The first argument in Random.nextInt is an exclusive upper bound, not inclusive. So with n=1 it will always return 0. for n=2 it will return either 0 or 1 which is what you're looking for.

answered Sep 05 '16 at 01:01

Daan van der Kallen

523
3
11

Creating a coin flip class

2 Answers2