0

I have this simple script:

 #!/usr/bin/ksh

while read param1 param2
do
        echo "Parameter1: $param1 - 1"
        echo "Parameter2: $param2 - 2"
done <<< "$(list.ksh)"

The script list.ksh calls a Java servlet and then returns a list of servers in this style:

192.168.1.1 server1
192.168.1.2 server2

In the output of my simple script I get the following result:

Parameter1: 192.168.1.1 - 1
 - 2 eter2: server1
Parameter1: 192.168.1.2 - 1
 - 2 eter2: server2

As you can see, the output of echo "Parameter2: $param2 - 2" is a completely strange line. For example, the number 2 at the end of the line appears in the beginning of the output.

I have spent some much time analyzing it, but I have not gotten anything.

Do you have any idea? Maybe the output from the servelet comes with 'broken' characters?

UPDATE:

I could solve this problem after reading the comments/answer below.

I just had to replace the /r /n from the servlet with the '/n' according to the unix style:

I've made it in one line: 

param2="$(echo $param2 | dos2unix)"

You can find a lot of information here: Remove carriage return in Unix

Community
  • 1
  • 1
vinicius.olifer
  • 101
  • 10

1 Answers1

2

Maybe the output from the servelet comes with 'broken' characters?

Not broken per se, but it's returning CRLFs instead of just LFs which is causing the strange output. Strip the CRs before using the data.

Ignacio Vazquez-Abrams
  • 776,304
  • 153
  • 1,341
  • 1,358