I have a form in which I have a type="file"
and a type="submit"
, now I need to send the chosen file to server, but the problem is that whenever I submit my form I get a huge apache error saying:
HTTP Status 500 - org.apache.tomcat.util.http.fileupload.FileUploadBase$InvalidContentTypeException: the request doesn't contain a multipart/form-data or multipart/mixed stream, content type header is application/x-www-form-urlencoded
Here is my client-side script:
<form method="POST" action="../propicuploader">
<div class="browsephoto_div">
<label class="takeapicture_btn">
<input type="file" accept=".png, .gif, .jpeg, .jpg" id="imagetoupload" enctype="multipart/form-data" onchange="document.getElementById('myImg').src = window.URL.createObjectURL(this.files[0])" required/>
<span>Browse</span>
</label>
</div>
<div class="ProfilePicsubmit_div">
<input type="submit" class="Profilpicsubmit_btn" value="Next"/>
</div>
</form>
My Server side script:
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
PrintWriter out = response.getWriter();
String description = request.getParameter("description"); // Retrieves <input type="text" name="description">
Part filePart = request.getPart("file"); // Retrieves <input type="file" name="file">
String fileName = Paths.get(filePart.getSubmittedFileName()).getFileName().toString(); // MSIE fix.
InputStream fileContent = filePart.getInputStream();
File file = new File("D:\\image123.jpg");
file.createNewFile();
OutputStream stream = new DataOutputStream(new FileOutputStream(file));
IOUtils.copy(fileContent,stream);
}
I am using apache v9.0 and java EE 8