shell script if[-n "$var"] returns No such file

Asked Sep 08 '16 at 11:51

Active Sep 08 '16 at 12:03

Viewed 18 times

I have this single-line script:

while read line; 
    do grepresult=`grep -l -r "$line" | head -1`; 
    if[-n "$grepresult"] then 
        echo "$grepresult" 
     else
        echo "$line" fi;
 done < /tmp/list.txt > out.txt

This reads from a file a series of lines and tries to find them in a directory tree using with the grep. If it finds the text in this line, it writes the file, otherwise it should write the not found text. The script works fine, however I am getting trouble and I get for each line an error: No such file or directory.

Any idea why this error happens?

edited Sep 08 '16 at 12:03

Peter G.

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asked Sep 08 '16 at 11:51

daniel sp

You need spaces between `[` and arguments. – 123 Sep 08 '16 at 11:53
Add some spaces: `if [ -n "$grepresult" ]` – redneb Sep 08 '16 at 11:53
Adding spaces it complains: syntax error unexpected token 'done' – daniel sp Sep 08 '16 at 11:56
1

Use `shellcheck.net` to fix the more obvious errors before posting here. – chepner Sep 08 '16 at 12:02

shell script if[-n "$var"] returns No such file

0 Answers0