dashcode error with java array se.mebe.Lion@7852e922, se.mebe.Zebra@4e25154f, se.mebe.Monkey@70dea4e

Question

public void addAnimalsToZoo() {

    Animal[] zoo = new Animal[animals.length + 5];
    System.arraycopy(animals, 0, zoo, 0, animals.length);

    for (count = 0; count < zoo.length; count++)
        System.out.println("new animals with new array" + "\t" + zoo[count]);

}

@JOJO read the answer. it tells you what to do, and it explains why you now get such results. — Stultuske, Sep 09 '16 at 11:18

score 0 · Answer 1 · answered Sep 09 '16 at 11:16

0

You didn't override the toString method in your Animal class.

System.out.println("new animals with new array" + "\t" + zoo[count]);

will print a concatenation of "new animals with new array", "\t" and the result of toString called on zoo[count].

If you don't override toString, the default one (from the Object class) will be used, which results in prints like: se.mebe.Zebra@4e25154f

answered Sep 09 '16 at 11:16

Stultuske

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did you mean like this System.out.println("new animals with new array" + "\t" + toString(zoo[count])); – JOJO Sep 09 '16 at 11:19
you need to override toString() in your Animal class – Stultuske Sep 09 '16 at 11:20
no. I mean something like: public String toString(){ return "result"; } – Stultuske Sep 09 '16 at 11:21
i tried but problem with return array , how to return the result in this case – JOJO Sep 09 '16 at 11:22
you're not printing the array, you are printing an element from the array. – Stultuske Sep 09 '16 at 11:34

dashcode error with java array se.mebe.Lion@7852e922, se.mebe.Zebra@4e25154f, se.mebe.Monkey@70dea4e

1 Answers1