How to get last 3 digits after comma?

Question

For a number that is 32,146 ...how do I find only 146? Is this able to be done?

findnum = '32,146'
return findnum

Possible duplicate of [python: how to get numbers after decimal point?](http://stackoverflow.com/questions/3886402/python-how-to-get-numbers-after-decimal-point) — Daniel, Sep 09 '16 at 20:42
it's a string. find the comma, then substring everything after it. — Marc B, Sep 09 '16 at 20:42

score 4 · Answer 1 · edited Sep 09 '16 at 20:47

4

Work with split

>>> findnum = '32,146'
>>> findnum.split(',')
['32', '146']

edited Sep 09 '16 at 20:47

Andrea Corbellini

answered Sep 09 '16 at 20:42

rafaelc

Reut Sharabani · Answer 2 · 2016-09-09T20:46:49.153

1

If you want the number you can do:

# get number by ignoring commas
number = int(findnum.replace(',',''))

# get last three digits
last_three = number % 1000

This will result in 146 (int) and not '146' (string)

Example:

>>> findnum = '32,146'
>>> number = int(findnum.replace(',',''))
>>> number % 1000
146

edited Sep 09 '16 at 20:46

answered Sep 09 '16 at 20:44

Reut Sharabani

score -1 · Answer 3 · answered Sep 09 '16 at 20:44

-1

Since its a string and not a number:

Can use slicing after the ',' to the end:

s[s.index(',')+1:]

answered Sep 09 '16 at 20:44

chenchuk

`s = '1,000,000'` `s[s.index(',')+1:]` results in '000,000' – Alexander Sep 09 '16 at 20:59

3 Answers3