Ajax won't work if using multiple params

Question

This is my AJAX code:

$.ajax({
        type: "POST", 
        url: "ajax.php", 
        data : params+'&lakasid='+lakasid,
        dataType: "json",

This code works perfectly, but when I add one more parameter to the data field, the request will not start.

Wrong code:

$.ajax({
    type: "POST", 
    url: "ajax.php", 
    data : params+'&lakasid='+lakasid+'&action='+action,
    dataType: "json",

When I add action at the end, the code is not working.

What could be the problem?

Thanks in advance.

What error are you getting? Could you share the rest of that function? You are at least missing a `})`. — PhilTrep, Sep 11 '16 at 11:57
Can't you use an anonymous object for the data? `data: { field1: "result1", field2 : "result2"}` Also I think your data url should be `params+'?lakasid='+lakasid+'&action='+action,` — Canvas, Sep 11 '16 at 11:57
@Canvas I agree that an Object should be used for `data`, because this will ensure that escaping is done correctly. But the `?` separates the path from the params and `data` (if used for `GET`) is already the part the is appended by jQuery to the `url` using the `?`. So either `params` is a string containing already other parameters and `&` is correct or `params` is already wrong. — t.niese, Sep 11 '16 at 12:00
If i console.log the code from params to action, it will look like the following: datum=2016-09-15&gaz=12&aram_nappali=13&aram_ejjeli=14&viz1=15&lakasid=19&action=save, @PhilTrep I just copied the top of the function it's much longer, but the problem I think is only with the url, because if I don't use the last parameter it is working. I don't get any errors. — Tibor, Sep 11 '16 at 12:12

score 0 · Accepted Answer · answered Sep 11 '16 at 12:14

Really you should use an object for data, like so:

var params = {
  'lakasid': lakasid,
  'action': action
};

$.ajax({
    type: "POST", 
    url: "ajax.php", 
    data : params,
    dataType: "json",

It would also be helpful to see the specific error you're receiving so that troubleshooting is easier.

score 0 · Answer 2 · edited May 23 '17 at 10:33

0

I believe ultimately your question can be answered here where there are multiple solutions:

How to pass parameters in $ajax POST?

edited May 23 '17 at 10:33

Community

1
1

answered Sep 11 '16 at 12:48

meditari

131
2
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Ajax won't work if using multiple params

2 Answers2