Javascript has lot's of "tricks" around types and type conversions so I'm wondering if these 2 methods are the same or if there is some corner case that makes them different?
5 Answers
They are not completely the same, and actually, the String constructor called as a function (your first example), will at the end, call the toString
method of the object passed, for example:
var o = { toString: function () { return "foo"; } };
String(o); // "foo"
On the other hand, if an identifier refers to null
or undefined
, you can't use the toString
method, it will give you a TypeError
exception:
var value = null;
String(null); // "null"
value.toString(); // TypeError
The String
constructor called as a function would be roughly equivalent to:
value + '';
The type conversion rules from Object-to-Primitive are detailed described on the specification, the [[DefaultValue]]
internal operation.
Briefly summarized, when converting from Object-to-String, the following steps are taken:
- If available, execute the
toString
method.- If the
result
is a primitive, returnresult
, else go to Step 2.
- If the
- If available, execute the
valueOf
method.- If the
result
is a primitive, returnresult
, else go to Step 3.
- If the
- Throw
TypeError
.
Given the above rules, we can make an example of the semantics involved:
var o = {
toString: function () { return "foo"; },
valueOf: function () { return "bar"; }
};
String(o); // "foo"
// Make the toString method unavailable:
o.toString = null;
String(o); // "bar"
// Also make the valueOf method unavailable:
o.valueOf = null;
try {
String(o);
} catch (e) {
alert(e); // TypeError
}
If you want to know more about this mechanism I would recommend looking at the ToPrimitive
and the ToString
internal operations.
I also recommend reading this article:

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4There is a third "way", if you call this: `new String(value)` on any value, it will always return a string object. – Herbertusz Dec 31 '16 at 20:31
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1@Herbertusz `new String({toString: null})` throws a `TypeError`. – Константин Ван Jul 10 '19 at 06:59
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With the addition of Symbols `String()` and `+ ''` now have a fairly significant difference. `String(Symbol())` will run, but `Symbol() + ''` will throw an error (and Symbol() will pass a falsey guard, unlike null and undefined, so `x && (x + '')` can now throw). – yeerk Aug 06 '19 at 14:51
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Looks like null doesn't have toString and valueOf methods, but String(null) returns 'null' without throwing error. Special behaviour? – szhuravel Nov 04 '21 at 14:29
value.toString()
will cause an error if value
is null or undefined. String(value)
should not.
For example:
var value = null;
alert(value.toString());
will fail because value == null
.
var value = null;
alert(String(value));
should display a message reading "null" (or similar), but it will not crash.
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3I've never seen a null pointer exception in javascript... where did you see that? – Dagg Nabbit Oct 15 '10 at 18:59
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@no, @casablanca Fixed. I'm used to Java. @mykhal How does that look? – Jonathan Oct 15 '10 at 19:07
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String(value)
should have the same result as value.toString()
in every case, except for values without properties like null
or undefined
. ''+value
will produce the same result.

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1`''+value` might not produce the same result as `String(value)` if `value` has both a `toString()` method and a `valueOf()` method. For example if `value = {toString(){return "Hello World!"}, valueOf(){return 3}}`, then `String(value)` will be `"Hello World!"` but `''+value` will be `3`. This is because the `+` operator looks for `valueOf` before `toString`, whereas `String(...)` only looks for `toString`. – Donald Duck Sep 01 '22 at 10:04
I just tried this with ES6 and found out that for String()
to look at valueOf()
inside of the object, the object has to have toString()
method. If the object does not have toString()
then console returns '[object Object]'
regardless of having valueOf()
or not. So in the the first "step", we always have to have toString()
regardless, else String()
method wouldn't look at valueOf
.
Please check this:
let obj = {
name:'b',
age:22,
valueOf: function(){
return 'heeee';
}
}
String(obj); // prints '[object Object]'
On the other hand,
let obj = {
name:'b',
age:22,
toString:null,
valueOf: function(){
return 'heeee';
}
}
String(obj); // prints 'heeee'
let obj = {
name: 'b',
age: 22,
valueOf: function() {
return 'heeee';
}
}
console.log(String(obj));
let obj2 = {
name: 'b',
age: 22,
toString: null,
valueOf: function() {
return 'heeee';
}
}
console.log(String(obj2));

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Abstract Operation is working under the cover. If the value to be converted is an Object, ToPrimitive Abstract operation is first called. Which calls toString or valueOf. If the object is capable of being converted into more than 1 primitive types then Hint is passed. In above, object is String Object so toString will be called. If it returns the primitive value, then convert to string (if not already string). If returns a non primitive value then valueOf is called to get primitive value (to convert into string if not string via ToString Abstract method) otherwise Type Error is thrown. – Sadiq Jul 28 '23 at 12:16
String() [the constructor call] is basically calling the .toString()
.toString() and String() can be called on primitive values(number,boolean,string) and basically will do nothing special:
true => 'true'
false => 'false'
17 => '17'
'hello' => 'hello'
But calling these functions on objects is where things gets interesting:
if the object has it's own .toString() function it will be called when ever you need this object to be treated as a string(explicitly/implicitly)
let obj = {
myName:"some object",
toString:function(){ return this.myName; }
}
//implicitly treating this obj as a string
"hello " + obj; //"hello some object"
//OR (explicitly)
"hello " + String(obj) //calling the existent toString function
//OR
"hello " + obj.toString(); //calling toString directly
By the way if you want to treat this object as a number it should has a .valueOf() function defined in it.
what if we have both in one object?
if we want to treat this object as a string => use .toString()
if we want to treat this object as a number => use .valueOf()
what if we only have .valueOf() defined?
.valueOf() defined inside the object will be called whether we want to handle the object as a string or as a number

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