Am I using the ternary operator?

Question

Here is my code:

echo "<option value=".$crew_rank_id.".(($crew_rank_id == $crew_rank) ? "selected" : "").>".$crew_rank_table."</option>";

what im trying to do is echo out the selected value from the database in echo

google it. Use this forum to ask questions regarding the problem you are facing. And for your question you are using ternary operatory but your `"` are not balanced — Atal Kishore, Sep 14 '16 at 06:11
The problem with your code is that you are mixing PHP statements in a string and your quotes and HTML tags are misplaced. — M. Eriksson, Sep 14 '16 at 06:13

score 0 · Answer 1 · edited Sep 18 '16 at 20:19

0

try this, check $crew_rank_id == $crew_rank store in variable and assign to it in <option> tag

$selected = "";
if($crew_rank_id == $crew_rank)
{
    $selected = "selected";
}

echo "<option value=".$crew_rank_id.".$selected.>".$crew_rank_table."</option>";

edited Sep 18 '16 at 20:19

Mr Lister

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answered Sep 14 '16 at 06:12

Dave

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your code don't have and error but it doesnt echo the correct value – Adi Sep 14 '16 at 06:17

score 0 · Answer 2 · answered Sep 14 '16 at 06:14

You are missing a double quotes in several places. The first one got the value and the "selected" to be one word, without spacing. The second before the closing of the option tag.

echo "<option value=".$crew_rank_id." ".(($crew_rank_id == $crew_rank) ? "selected" : "").">".$crew_rank_table."</option>";

score 0 · Accepted Answer · answered Sep 14 '16 at 06:17

0

Your mixing PHP statements and PHP variables in the string and have some missing quotes and HTML-tags.

This should work:

echo "<option value='{$crew_rank_id}' ". (($crew_rank_id == $crew_rank) ? "selected" : "") . ">{$crew_rank_table}</option>";

answered Sep 14 '16 at 06:17

M. Eriksson

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man thanks. your code did work – Adi Sep 14 '16 at 06:21

Am I using the ternary operator?

3 Answers3