pass variable to replace function regular expression javascript

Question

I want to have a 'newline'-function to pass a string to it and print it on pdf. my function so far is

var array = new Array();
function newLineFunction_PDF(text) {
  var arr = text.replace(/.{70}\S*\s+/g, "$&@").split(/\s+@/);
  return arr;
}

array = newLineFunction_PDF('some Text');

for( var i in array) {
  print(array[i]);
}

What it does is cut the text in to pieces of length-70 incl. the last word, push it into the array and print it afterwards with new lines. Now i want to pass a number to the function, like 100, so i can decide the max-length of the text per line.

So far I tried:

function newLineFunction_PDF(text, num) {
  var re = new RegExp(/.{num}\S*\s+/g);
  var arr = text.replace(re, "$&@").split(/\s+@/);
  return arr;
}

but I dont know how and where to add escapes into the new RegExp.

score 1 · Accepted Answer · answered Sep 14 '16 at 08:46

1

The parameter of Regexp is a string:

 var re = new RegExp('.{' + num + '}\S*\s+', 'g');

answered Sep 14 '16 at 08:46

Toto

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with escaping the backslashes it works :) – moody Sep 14 '16 at 10:34

pass variable to replace function regular expression javascript

1 Answers1