How to replace a [] in bash script?

Question

I am writing a bash script for installing django with postgresql database automatically. Now , I want to replace database name by command ,since it is using sqlite3 database file path.

I wrote this command:

sudo sed -i "s/ALLOWED_HOSTS = []/ALLOWED_HOSTS = ['*']/g"  $project_name/settings.py

But it shows me this error:

sed: -e expression #1, char 44: unterminated `s' command

How to change this , please help me.

You should [edit] your question to show us an example of the input and the corresponding desired output. — Tom Fenech, Sep 14 '16 at 09:31

Inian · Accepted Answer · 2016-09-14T09:41:23.277

1

Escape the single-quotes as below:-

sed -i "s/ALLOWED_HOSTS = \[\]/ALLOWED_HOSTS = \['*'\]/g" file

edited Sep 14 '16 at 09:41

answered Sep 14 '16 at 09:28

Inian

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I'm not sure why the quotes would need to be escaped here. – Tom Fenech Sep 14 '16 at 09:34
@TomFenech: Fixed it thanks! – Inian Sep 14 '16 at 09:47
The `[` and `]` in the replacement string don't need to be escaped either. Neither does the `]` in the search string (but I can see why people would do that). – Tom Fenech Sep 14 '16 at 09:49
@Inian Thanks for solving it. – HM Tanbir Sep 14 '16 at 09:50
@Engr.TanbirHasan: Happy to help! But please do a bit of search in the community before posting new questions. Thanks! – Inian Sep 14 '16 at 09:51

How to replace a [] in bash script?

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