PHP array of arrays: get a list of values for a given attribute

Question

suppose i have an array of arrays in PHP:

$array = [
    ['value'=>1, 'other_attribute'=>'whatever'],
    ['value'=>13, 'other_attribute'=>'whatever'],
    ['value'=>45, 'other_attribute'=>'whatever'],
    ['value'=>64, 'other_attribute'=>'whatever'],
];

how can i get a list containing just a specific attribute of each of the array's elements? in my case, if i wanted to get the list of 'value', the output should look like this: [1, 13, 45, 64]

using the Laravel framework, it's easy to do this with query builder objects, simply like this: $array->lists('value');. is there a way to do this in plain PHP?

And check the highest scoring answer for the duplicate, rather than simply the accepted answer — Mark Baker, Sep 14 '16 at 15:59

score 1 · Answer 1 · answered Sep 14 '16 at 15:57

1

Sure, just build your own loop to do it:

$values = []; // the new array where we'll store the 'value' attributes
foreach ($array as $a) { // let's loop through the array you posted in your question
    $values[] = $a['value']; // push the value onto the end of the array
}

answered Sep 14 '16 at 15:57

Hayden Schiff

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2

`$values = array_column($array, 'value');` is much easier – Peter Featherstone Sep 14 '16 at 16:09

PHP array of arrays: get a list of values for a given attribute

1 Answers1