XML Remove node without changing other nodes

Asked Sep 17 '16 at 16:06

Active Sep 17 '16 at 16:06

Viewed 31 times

Here is my code. It removes cubes comparing cube attribute "name" against a value I passed as a variable to the method. But the issue is it change other nodes (dimension,other ) in the xml file.

<schema>
    <dimension..../>
    <cube name="..." .../>
    <others ..>
</schema>

What I can do to prevent other nodes getting changed ?

XPathFactory xpf = XPathFactory.newInstance();
XPath xpath = xpf.newXPath();
String expressionQuery = String.format("//Schema/Cube[@name=\"%s  \"]",cubeName);
XPathExpression expression = xpath.compile(expressionQuery);

Node nodeToRemove = (Node) expression.evaluate(document, XPathConstants.NODE);
if(nodeToRemove != null) {
    nodeToRemove.getParentNode().removeChild(nodeToRemove);
}

asked Sep 17 '16 at 16:06

rinjan

Changes in what way? – Dark Falcon Sep 17 '16 at 16:08
sort attributes to alphabetic order. – rinjan Sep 17 '16 at 16:10
Why is that a problem?? – Carlitos Way Sep 17 '16 at 16:12
We prefer name attribute as the first attribute in the node. In our scenario it is like a unique identification value. If the name attribute go to the middle of the element it would be difficult to read – rinjan Sep 17 '16 at 16:16

XML Remove node without changing other nodes

0 Answers0