Python - text file with all values 0 to 2^24 in HEX

Question

I am trying to create a file with all possible values for 0 up to 2^24 in HEX.

This is what I have so far:

file_name = "values.txt"
counter = 0
value = 0x0000000000
with open (file_name, 'w') as writer:
    while counter < 16777216:
        data_to_write = str(value) + '\n' 
        writer.write(data_to_write)
        counter = counter + 1
        value = value + 0x0000000001

This do what I want but with integers. Is there an easy way to turn this to HEX values in file instead (still as string)?

Thank you

"all possible values for 2^2" - you're going to have to explain what you mean by that. I only see two possible values for 2^2: 0, if ^ is XOR, or 4, if ^ is exponentiation. You seem to be trying to say something completely different. — user2357112, Sep 19 '16 at 07:38
I tried: data_to_write = str(hex(value)) + '\n' But then I get 0x first, so then I need to remove that somehow... — Matrilx, Sep 19 '16 at 07:42
Possible duplicate of [Python Hexadecimal](http://stackoverflow.com/questions/14678132/python-hexadecimal) — SiHa, Sep 19 '16 at 11:27

score 0 · Answer 1 · answered Sep 19 '16 at 07:41

0

just use the format method from string when writting:

writer.write("{:#X}".format(data_to_write))

Example:

>>> "{:#x}".format(123324)
'0x1e1bc'
>>> "{:#X}".format(123324)
'0X1E1BC'

answered Sep 19 '16 at 07:41

Netwave

40,134
6
50
93

score 0 · Answer 2 · answered Sep 19 '16 at 07:56

0

Thank you for your help.

It is working now:

file_name = "value.txt"
counter = 0
value = 0x0000000000
with open (file_name, 'w') as writer:
    while counter < 10000:
        data_to_write = str(hex(value)[2:].zfill(6)) + '\n' 
        writer.write(data_to_write)
        counter = counter + 1
        value = value + 0x0000000001

answered Sep 19 '16 at 07:56

Matrilx

3
3

1

You could use `"{:010x}".format(value)` for a bit more readability. – Phylogenesis Sep 19 '16 at 08:03

Python - text file with all values 0 to 2^24 in HEX

2 Answers2