Shifting Math.ceil in Java

Question

I want to perform a ceiling function on a number (33.1504352455) so that it returns 33.16. When using ceiling, of course, it returns 34.0. How would I shift the character that the ceiling is acting on so that it returns 33.16?

Possible duplicate of [How to round a number to n decimal places in Java](http://stackoverflow.com/questions/153724/how-to-round-a-number-to-n-decimal-places-in-java) — Gerard Roche, Sep 23 '16 at 17:24

score 2 · Answer 1 · answered Sep 23 '16 at 15:48

2

You could try

number = Math.ceil(oldnumber * 100) / 100.0;

But this could be subject to the vagaries of floating point math.

answered Sep 23 '16 at 15:48

ControlAltDel

33,923
10
53
80

score 2 · Accepted Answer · answered Sep 23 '16 at 15:49

2

For better precision, always opt for BigDecimal. You could do it like:

BigDecimal b = new BigDecimal(33.1504352455);
b = b.setScale(2, RoundingMode.CEILING)
System.out.println(b);

answered Sep 23 '16 at 15:49

SMA

36,381
8
49
73

Shifting Math.ceil in Java

2 Answers2