How to convert string to UInt32?

Question

I am a beginner in swift and I am having a problem with convering string to UInt32.

   let Generator = (ReadableJSON ["People"] [Person]["F1"].string! as NSString).doubleValue

    if Generator == 1 {

        NameLabel1 = ReadableJSON ["People"] [Person]["A1"].string as String!
        NameImeNaObekt = ReadableJSON ["People"] [Person] ["B1"].string as String!
        Picture = ReadableJSON ["People"] [Person] ["E1"].string as String!

    } else {

         let RGen = arc4random_uniform ("\(Generator)") // here is the error

    }

Would you advise me how to fix it. The problem is in the last line, which is red and it says Cannot convert value of type String to UInt32. The main idea is that I am reading the number from a JSON file and I have to populate this number into the arc4random_uniform.

Since you are a beginner in Swift please learn first to consider the naming convention that variable names start with a lowercase letter. — vadian, Sep 23 '16 at 19:43

Arashk · Accepted Answer · 2016-09-23T19:52:19.483

1

arc4random_uniform(UInt32)

accept an UInt32 value but you are passing an String value to it

this converts your number to string

"\(Generator)"

the last line should be like this

let RGen = arc4random_uniform (UInt32(Generator))

and if you want to 'RGen' is an String you can do it this way

"\(RGen)"
String(RGen)

edited Sep 23 '16 at 19:52

answered Sep 23 '16 at 19:36

Arashk

617
5
16

The number behind the generator should be displayed into arc4random_uniform – Dakata Sep 23 '16 at 19:37
as your 'Generator' is double so your code should be like this arc4random_uniform(UInt32(Generator)) – Arashk Sep 23 '16 at 19:41

score -1 · Answer 2 · edited May 23 '17 at 12:32

-1

     var RGen= 0

     let RGen =int( arc4random_uniform ("\(Generator)")  )

or let RGen =( arc4random_uniform ("(Generator)") ).toInt

Look here

edited May 23 '17 at 12:32

Community

1
1

answered Sep 23 '16 at 19:39

GDutton

164
14

How to convert string to UInt32?

2 Answers2