Exclude only 0 in regular expression javascript

Question

I want to create a regular expression which will take one to ten numeric value but it should not accept if only 0's are provided

for example

1 is valid input
1111123455 is valid input
01 is valid input
010 is valid input
0000 is not valid input
0 is also not valid input
0000000000 is also not valid input

i tried regex

^([0-9]{1,10}|)$

which accepts ten numeric but how to avoid only 0's

http://stackoverflow.com/questions/7036324/what-is-the-regex-for-any-positive-integer-excluding-0 — Wiktor Stribiżew, Sep 27 '16 at 10:11
So, is `0123` valid? or is only `1230` valid - can you _start_ with zero or is it a positive number? EDIT: answered just as I was commenting. — VLAZ, Sep 27 '16 at 10:12
@this.lau_ i dont want to call function or validate otherwise if it could be done with with regex — Vicky Kumar, Sep 27 '16 at 10:13

score 10 · Accepted Answer · edited May 23 '17 at 10:34

10

You may use a negative lookahead:

^(?!0+$)[0-9]{1,10}$

See the regex demo

Details:

^ - start of string
(?!0+$) - no just zeros are allowed up to the end of string
[0-9]{1,10} - 1 to 10 digits
$ - end of string.

NOTE: To also allow empty value, use 0 as the min argument in the limiting quantifier:

^(?!0+$)[0-9]{0,10}$
              ^

See How Negative Lookahead Works (more here) to learn more about how (?!0+) works in this pattern. In short: right at the start of the string, we check the whole string for just zeros. If there is a zero or more right after start of a string, the match is failed. Else, 1 (or 0) to 10 digits are matched and the result is returned.

edited May 23 '17 at 10:34

Community

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answered Sep 27 '16 at 10:15

Wiktor Stribiżew

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thanks @Wiktor this one is working if u can concept of negative lokahead it would be helpul thanks again – Vicky Kumar Sep 27 '16 at 10:19
I am just not sure why an empty alternative is used in the OP regex - `^([0-9]{1,10}|)$`. It may match an empty string. – Wiktor Stribiżew Sep 27 '16 at 10:19
it is also required if field is left empty then error should not be shown not important here – Vicky Kumar Sep 27 '16 at 10:21
The `[0-9]` can be simplified to just `\d`. – ruohola Nov 06 '19 at 15:17
@ruohola Yes, in JS, it can. However, in other regex flavors, like Python 3 `re` or .NET, `\d` will match all Unicode digits, and that is not what is expected in most cases. `\d` does not work across all regex flavors, e.g. POSIX. Thus, it is a good idea to keep to the character class solution, which is most portable. – Wiktor Stribiżew Nov 06 '19 at 15:22

score 2 · Answer 2 · answered Sep 27 '16 at 10:17

2

You can check this with Number function like this.No need of regex.

var str = '10001';
console.log(Boolean(Number(str))); This returns true if string does not contain only zeros and false if string contains only zeros

answered Sep 27 '16 at 10:17

ninjawarrior

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score 0 · Answer 3 · answered Sep 27 '16 at 10:38

You can use regex as :^(?=.*[1-9])\d{1,10}$

Explaination :

^ assert position at start of the string

(?=.*[1-9]) Positive Lookahead - Assert that the regex below can be matched .* matches any character (except newline) Quantifier: * Between zero and unlimited times, as many times as possible, giving back as needed [greedy]

[1-9] match a single character present in the list below 1-9 a single character in the range between 1 and 9

\d{1,10} match a digit [0-9] Quantifier: {1,10} Between 1 and 10 times, as many times as possible, giving back as needed [greedy]

$ assert position at end of the string

console.log("1".match(/^(?=.*[1-9])\d{1,10}$/));
console.log("1111123455".match(/^(?=.*[1-9])\d{1,10}$/));
console.log("0000".match(/^(?=.*[1-9])\d{1,10}$/));
console.log("0".match(/^(?=.*[1-9])\d{1,10}$/));
console.log("0000000000".match(/^(?=.*[1-9])\d{1,10}$/));

Exclude only 0 in regular expression javascript

3 Answers3

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