Avoiding Nested Lists

Question

What is the most Pythonic way to print the first element of each of the lists?

For example, I want ['apple', 'banana'] from the list of lists below:

data = [['apple','airplane'],['banana','boat']]

This is my best attempt:

fruit = [list(fruit) for fruit in data]

[letter[0] for letter in fruit]

However, having two list comprehensions doesn't seems very pythonic

well, the first list comprehension doesn't change anything: `[['apple','airplane'],['banana','boat']] == [list(fruit) for fruit in [['apple','airplane'],['banana','boat']]]` results in `True`... — Antti Haapala -- Слава Україні, Sep 28 '16 at 04:17

score 0 · Answer 1 · answered Sep 28 '16 at 04:09

0

Why not just

fruit = [fruit[0] for fruit in data]

That gets me the expected output, see below:

>>> data = [['apple','airplane'],['banana','boat']]
>>> fruit = [fruit[0] for fruit in data]
>>> print fruit
['apple', 'banana']

answered Sep 28 '16 at 04:09

user3543300

1 Answers1