Sending default parameter as null and use default value set in function

Question

I have function as below.

function test($username, $is_active=1, $sent_email=1, $sent_sms=1) {

  echo $sent_email;  // It should print default ie 1

}

Call to function :

  test($username, 1, null, 1);

How to call function if need to use default value in function. $sent_email should be 1. Can not change sequence of parameter.

Your function is doing too much and you see now why that is a problem. — PeeHaa, Sep 28 '16 at 12:28
Pass it an array of parameters `function test(array $params)` — RiggsFolly, Sep 28 '16 at 12:30
...and read [this thread](http://stackoverflow.com/questions/1620737/using-default-value-when-calling-a-function) — BVengerov, Sep 28 '16 at 12:31

score 0 · Accepted Answer · answered Sep 28 '16 at 12:46

When you start the value parameters happens:

 function makecoffee($type = "cappuccino")
    {
        return "Making a cup of $type.\n";
    }
    echo makecoffee();
    echo makecoffee(null);
    echo makecoffee("espresso");
    ?>

The above example will output:

Making a cup of cappuccino.
Making a cup of .
Making a cup of espresso.

To fulfill what you want to check with conditions as follows:

function test($username, $is_active=1, $sent_email=1, $sent_sms=1) {

    if($sent_email!=1)
        $sent_email=1;
      echo $sent_email;  // It should print default ie 1

    }

This will override __any meaningful__ value other than `1` with the default value. Use `if ($sent_email === null)` as the condition to replace only (non meaningful) `null` values. — Philipp Maurer, Sep 21 '18 at 12:16

score -1 · Answer 2 · answered Sep 28 '16 at 12:35

In php you cannot declare more than 1 parameter with default value in your function. Php could not know wich param you do not give if you have multiple default value...

In your case, you give the param, with null value. That's a lot different ! So, you can use the following :

function test($username, $is_active, $sent_email, $sent_sms) {
    $username = ($username != null) ? $username : 1;
    $is_active = ($is_active != null) ? $is_active : 1;
    $sent_email = ($sent_email != null) ? $sent_email : 1;

  echo $sent_email;  // It should print default ie 1

}

as it, if you give null, your function will use "1" value, and if not null, the value you pass as parameter ;)

"In php you cannot declare more than 1 parameter with default value in your function" Sure you can. — PeeHaa, Sep 28 '16 at 12:46

Sending default parameter as null and use default value set in function

2 Answers2