Is there any clean way of initializing an object with a variable key?

Question

I have two variable, attribute (e.g. "type") and value (e.g. "car"). I want to make an object where the key is the attribute (and the value is the value). Like this: {"type": "car"}.

When I do

let obj = { attribute: value }

I get

> {"attribute": "car"}

This is easy with two lines, as I can just

let obj = {};
obj[attribute] = value;

However, I'm wondering if there is a clean way of doing this in one line (since I'm a former Rubyist and I like making things clean and precise)?

(Also I feel this is a question that already has an answer here, but I could not find a similar question, so I apologize in advance if this is a duplicate) — Mike Manfrin, Sep 28 '16 at 19:58

ASDFGerte · Accepted Answer · 2016-09-28T20:02:57.797

1

Computed property names, starting from ES2015 aka ES6.

let a = "type", b = "car";
console.log({[a]: b});

edited Sep 28 '16 at 20:02

answered Sep 28 '16 at 19:59

ASDFGerte

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PERFECT! I knew there had to be something, but my coworkers and I were stumped. – Mike Manfrin Sep 28 '16 at 20:01
1

@MikeManfrin be aware that this won't necessarily work everywhere, at least for now. – Pointy Sep 28 '16 at 20:01
We're thankfully using typescript -> es6, so this should work for us, thank you! – Mike Manfrin Sep 28 '16 at 20:02

Is there any clean way of initializing an object with a variable key?

1 Answers1