Resolve variable read from file

Asked Sep 29 '16 at 12:10

Active Sep 29 '16 at 12:10

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I'm trying to read part of a line from a .txt file, which holds a filename. I use that filename to execute several commando's. However, the variable doesn't seem to resolve correctly.

file.txt

Lookup-File: file.tar.gz

code

lookupFileMD5=`grep -A1 ^Lookup-File $metadataFile | grep ^MD5-Digest | cut -d' ' -f2`
    echo "lookupFileMD5=$lookupFileMD5"
    lookupFileMD5downloaded=`md5sum $path/$lookupFileName | cut -d' ' -f1`

output

2016-09-29 13:57:00 [INFO] - ++ grep -A1 '^Lookup-File' file.txt

13:57:11 2016-09-29 13:57:02 [INFO] - ++ cut '-d ' -f1

13:57:11 2016-09-29 13:57:02 [INFO] - ++ md5sum $'/path/file.tar.gzr'

13:57:11 2016-09-29 13:57:02 [INFO] - md5sum: /path/file.tar.gz

13:57:11 : No such file or directory

problem

The actual filename is file.tar.gz but in the command (last line) it resolves to md5sum $'/path/file.tar.gzr', with the additional $'..r'.

edited Jun 20 '20 at 09:12

Community

asked Sep 29 '16 at 12:10

Lars de Bruijn

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Either your script or your text file uses DOS line endings; the `r` (presumably `\r`) is the carriage-return half of the line ending being included in the value. – chepner Sep 29 '16 at 12:14
@chepner Any ideas on how to fix this? – Lars de Bruijn Sep 29 '16 at 12:16
I see you marked it as duplicate, ignore my previous question – Lars de Bruijn Sep 29 '16 at 12:18

Resolve variable read from file

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