(Probably some typo in the HQL itself but the idea should be correct)
What you are asking, based on your SQL and description, is find out all Participation
(and its corresponding Group
) based on User
, which is simply
select p.id, p.group.id from Participation p where p.user.id = :userId
To make it better, you should fetch the entities instead:
from Participation p left join fetch p.group where p.user.id = :userId
There were some confusions in understanding what you were trying to do:
You want all groups (regardless of condition). And, for a given user, you want to find all groups and participations that user is involved.
Though it should be possible using Right-outer-join:
select g, p from Participation p
right outer join p.group g
where p.user.id=:userId
Or, in later version of Hibernate (>= 5.1 ?), it allow explicit join (haven't tried before, you may give it a try) (Replace with
with on
if you are using JPQL):
select g, p from Group g
left outer join Participation p
with p.group = g
left outer join p.user u
where u.id = :userId
Or you may use other techniques such as subquery etc. However I would rather separate them into simpler queries in your case and do a simple aggregation in your code.
The basic idea is to have
- Query for all groups:
from Groups
- Query for all participations for a user:
from Participation p join fetch p.group where p.user.id=:userId
Then you can aggregate them easily to the form you want, e.g. Map<Group, List<Participation>>
, or even more meaningful value object.
The benefit is the data access query is simpler and more reusable (esp if you are wrapping them in DAO/Repository finder method). One more round trip to DB shouldn't cause any obvious performance impact here.