unindent does not match any outer indentation level Coursera assignment

Question

Hi guys i just started with Python (3.5) trying to complete an assignment on Coursera and i keep getting the above error

Age = 15
if Age >=15 :
    print ("Highschool")
   else if
       print ("No HighSchool")

Is this Python syntax? `else if` should be `elif:`. And your indentation is off — Moses Koledoye, Oct 04 '16 at 15:35
My 'unclear what you're asking' close vote came before the edit. Now it's pretty clear. — orlp, Oct 04 '16 at 15:36

score 1 · Answer 1 · answered Oct 04 '16 at 15:43

Python, unlike many programming languages, relies on indentation to dictate scope. In particular, it permits tabs or certain number of spaces to indicate scope. Contiguous lines with the same indentation level are all in the same scope.

Your code:

Age = 15
if Age >=15 :
    print ("Highschool")
   else if
       print ("No HighSchool")

Has indentation that is uneven, which confuses the python interpreter. You seem to be using 4 spaces to indicate indentation, but your else if statement (should be else: by the way) is not at any indentation level that makes sense. You use 3 spaces before the else if statement. You should actually be using 0 spaces, as it is operating at the same scope/level of the if statement.

Age = 15
if Age >=15 :
    print ("Highschool")
else:
    print ("No HighSchool")

Read more about Python's whitespace here.

score 0 · Answer 2 · answered Oct 04 '16 at 15:43

The problem is that the else matching an if MUST occur at exactly the same indentation level as the if. Also, there's no need for another if following the else. Try

Age = 15
if Age >=15:
    print ("Highschool")
else:
    print ("No HighSchool")

You should find that works better· Remember the colons - they are important!

unindent does not match any outer indentation level Coursera assignment

2 Answers2