Round off Decimal at application level in C#

Question

In our application there are around 200 decimal variables,Is there any way which we can round off decimal to 2 places before assignment.

Or any application level config to achieve this

Currently we are try to achieve using Extension method below

public static decimal RoundOff(this decimal value)
{
   return Math.Round(value,2);
}

Do you want **every** decimal to be automagically rounded at 2 decimals and ignore every digit after that? — zdimension, Oct 04 '16 at 18:57
What do you want to happen if you add two decimals? Should they be truncated before or after the addition? — Roger Lipscombe, Oct 04 '16 at 19:02
value should be truncated before the assignment,so that the result we get is a decimal with truncated value. — Vikas Sardana, Oct 04 '16 at 19:06

score 3 · Answer 1 · edited May 23 '17 at 11:48

3

No, there is no way to control number of decimal places stored in values of decimal type.

You can either round values via code as you do now, or maybe just output values with 2 decimal points (c# - How do I round a decimal value to 2 decimal places (for output on a page))

edited May 23 '17 at 11:48

Community

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answered Oct 04 '16 at 18:59

Alexei Levenkov

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InBetween · Accepted Answer · 2016-10-04T19:32:42.253

It depends. If calculation correctness depends on the variables being rounded previously then just formatting the output is not an option. You could keep using your extension method on every assignment but that is potentially error prone (you can miss one) or you can create a wrapper class:

public struct RoundedDecimal: IEquatable<RoundedDecimal>, IFormattable, IComparable<RoundedDecimal>
{
     private readonly decimal value;

     public RoundedDecimal(decimal value)
     {
          this.value = Math.Round(value, 2);
     }

     public static implicit operator RoundedDecimal(decimal value) =>
        new RoundedDecimal(value);

     public static explicit operator Decimal(RoundedDecimal value) =>
         value;

     public static RoundedDecimal operator *(RoundedDecimal left, RoundedDecimal right) =>
         new RoundedDecimal(left.value * right.value);

     //and so on
 }

So we have to replace all the `decimal` with `RoundedDecimal` — Vikas Sardana, Oct 04 '16 at 19:34

score 0 · Answer 3 · answered Oct 04 '16 at 19:02

Well, if you want every decimal to be rounded to two decimals, you could (veeeery ugly) make your own number struct with implicit operators for casting from and to decimal that round to two decimals. This way, when you write a decimal constant in your code and that it is passed to a function or field expecting , or vice-versa, it'll be automatically rounded at two decimals. But it's still better and cleaner to continue using your extension method.

Ugly? Why? I don't understand. – InBetween Oct 04 '16 at 19:16 — InBetween, Oct 04 '16 at 19:16

Round off Decimal at application level in C#

3 Answers3