switch/case problem

Question

If i try to create variable in case statement it gives me build erroe Can anyone clue me in why this syntax gets me a build error ("expected expression before 'NSMutableArray'").

possible duplicate of [Declaring variables inside a switch statement](http://stackoverflow.com/questions/1231198/declaring-variables-inside-a-switch-statement) — Vladimir, Oct 21 '10 at 12:02

score 5 · Accepted Answer · edited Dec 23 '11 at 16:16

5

Try adding brackets {} in your case statement to be able to declare variables, like this:

switch (my_switch_statement)
{
     case my_switch_case: 
     {
         NSMutableArray *my_switch_array;
     }
}

edited Dec 23 '11 at 16:16

Richard J. Ross III

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answered Oct 21 '10 at 12:10

Benoît

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Thanks Benoit. Adding curly braces fixed the issue – Swapna Oct 21 '10 at 12:17

score 4 · Answer 2 · answered Oct 21 '10 at 11:57

Assuming you try do something like:

switch (...){
  case someCase:
        NSMutableArray *array = ...
        break;
...
}

c (and so objective-c) does not allow to declare variables inside switch-case statement. If you want to do that you must limit the variable scope by putting your code inside {} block:

switch (...){
  case someCase:{
        NSMutableArray *array = ...
  }
        break;
...
}

score 0 · Answer 3 · edited Jun 10 '11 at 07:12

generally you will want to declare the variable outside of the scope of the switch, just like any conditional block of code.


NSString * valueString;

int i = 1;

switch(i){

    case 0:

         valueString = @"case 0";

    break;

    case 1:

         valueString = @"case 1";

    break;

    default:

         valueString = @"not case 1 or 0";

    break;

}

//valueString=>@"case 1"

switch/case problem

3 Answers3