php regex to get strings that start with any character and end with open brace

Question

I have css file that I am trying to manipulate using php. So if my css is like...

.something {
    display:none;
    background: blue;
}

.somethingElse {
    display:block;
}

I want to be able to get an array of the class names. So my array would look like...

['.something', '.somethingElse']

This is my attempt ($homepage is my css file)...

$homepage = file_get_contents("style.css");
$regex = '/[\s\S]\K[^{]*(?=})/m';
preg_match_all($regex, $homepage, $matches);

What I tried to do was find all strings that start with any character and end in open brace {. My regex is all wrong, what is the proper way?

Try `'~^\h*\.([^\n{]*?)\s*{~m'`. To parse arbitrary CSS, use a CSS parser. See [Parse a CSS file with PHP](http://stackoverflow.com/questions/3618381/parse-a-css-file-with-php). — Wiktor Stribiżew, Oct 05 '16 at 17:33
I think you'd be better served with a CSS parser written in PHP. — Matt S, Oct 05 '16 at 17:34
What about multiple class names for one single CSS block? What if id names or other different selectors are between them? — revo, Oct 05 '16 at 17:34

ByteBit · Accepted Answer · 2016-10-05T18:26:36.557

1

This should work great:

\.([\w]+)\s*{

The class name is in group #1.

Example:

preg_match_all("/\.([\w]+)\s*{/", $homepage, $matches);

edited Oct 05 '16 at 18:26

answered Oct 05 '16 at 17:39

ByteBit

1 Answers1