bash script - Iterate list of files without extention in a directory

Question

I want to iterate all the files in a directory in a bash script.

1. List all files with extentions .LOG .txt .MAP .TL9*
2. List all files which have no extention.

I am trying this :

for file in *.{LOG,txt,MAP,TL9*}; do

I want to list the files, that only ends with above extension. So, I do not want to list a file: temp.txt.EXT because it does not end with above given extentions. Similarly I don't want this to be reported temp.TL94.JPG or temp.TL9.JPG.

But in this above for loop, how do i insert the check which gives me the file with no extention?

Please help.

Answer 1

Using extglob, you can do this:

shopt -s nullglob
shopt -s extglob

for file in @(!(*.*)|*.@(csv|LOG|TL9!(*.*))); do
   echo "$file"
done

Answer 2

With extglob:

*.@(LOG|txt|MAP|TL9) !(*.*)

• *.@(LOG|txt|MAP|TL9) matches all .LOG, txt, .MAP, and .TL9 files

• !(*.*) matches all files except ones having . in name

Enable extglob first if not enabled:

shopt -s extglob

Answer 3

You could also use the find command to list files with extension MAP, LOG, TL9or without any extension at all.

#!/bin/bash

files=`find . -type f -regex ".*[\.LOG|\.MAP|\.TL9]" -o ! -name "*.*"`

for file in $files
do
  echo $file
done