Regex find ALL patterns between string

Question

I want to match digits betwen "000" or betwen \b and "000" or "000" and \b from a string like this:

11101110001011101000000011101010111

I have tried with expressions like this:

(?<=000)\d+(?=000)

but I only get the largest occurrence

I expect to get:

1110111
1011101
0
11101010111

Possible duplicate of [The 'g' flag in regular expressions](http://stackoverflow.com/questions/12993629/the-g-flag-in-regular-expressions) — The SE I loved is dead, Oct 07 '16 at 01:43

score 1 · Accepted Answer · edited May 23 '17 at 11:48

1

You can use the regex package and the .findall() method:

In [1]: s = "11101110001011101000000011101010111"

In [2]: import regex

In [3]: regex.findall(r"(?<=000|^)\d+?(?=000|$)", s)
Out[3]: ['1110111', '1011101', '0', '00011101010111']

The 000|^ and 000|$ would help to match either the 000 or the beginning and the end of a string respectively. Also note the ? after the \d+ - we are making it non-greedy.

Note that the regular re.findall() would fail with the following error in this case:

error: look-behind requires fixed-width pattern

This is because re does not support variable-length lookarounds but regex does.

edited May 23 '17 at 11:48

Community

1
1

answered Oct 07 '16 at 01:44

alecxe

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It didn't work, I tried this `(?<=000)[^0]\d+?(?=000|\b)|(?<=\b)[^0]\d+?(?=000|\b)` but now it doesn't get the 0 betwen "000" and "000" – Napoleón Cortés Oct 07 '16 at 02:05
I have solved!! Thanks, this is the code that works `(?<=000)[^0]\d+?(?=000|\b)|(?<=\b)[^0]\d+?(?=000|\b)|(?<=000)\d(?=000)` – Napoleón Cortés Oct 07 '16 at 02:10

score 1 · Answer 2 · answered Oct 07 '16 at 10:59

1

you can do it with the re module like this:

re.findall(r'(?:\b|(?<=000))(\d+?)(?:000|\b)', s)

answered Oct 07 '16 at 10:59

Casimir et Hippolyte

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Regex find ALL patterns between string

2 Answers2