Grep line without include double quote

Asked Oct 07 '16 at 06:08

Active Oct 07 '16 at 06:12

Viewed 37 times

I trying to grep a line which have double quotes. How can I do it without including double quotes.

export port="$(find ./pdf/myInventory/dyn_conf/group_vars/abc1/vars.yml -exec sh -c 'grep -A 3 -e ilink_nei_sri_host {} | grep -e port' \; | cut -d: -f2)"

export port_https=$(($abc_port + 81))

find ./pdf/myInventory/dyn_conf/group_vars/abc1/vars.yml  \
    -exec sed -i -e 's/port: \"${port}\"/port: \"${port_https}\"/g' {} \;

However, if the port has double quotes eg for port value: "20080" Im trying to replace with the port_https value and it become " "20080"" How can i make it just just to "20080"?

edited Oct 07 '16 at 06:12

Inian

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asked Oct 07 '16 at 06:08

Lee

1

Why would you run `find` on a single file? Simply `sed` it. – tripleee Oct 07 '16 at 06:28
could you change this; export port_https=$(echo $(($abc_port + 81))| sed 's/ //g') – Mustafa DOGRU Oct 07 '16 at 06:41

Grep line without include double quote

0 Answers0