how to NOT cut off the last char with substr?

Question

Got following String: http://example.de/?param=1&param2=http://example2.com/ I want to get everything behind param2=. First thought was substr, but it never gives me all behind param2=. No matter how I use it, it always returns http://example2.com (last char missing). I red the Documentation for this, but still no success with this.

I already tried:

$url = 'http://example.de/?param=1&param2=http://example2.com/';

$piece = substr($url, strpos($url, 'param2=') + 7 ,count($url)); //+7 cause of param2= should not be included
=> h

$piece = substr($url, strpos($url, 'param2=') + 7 , -count($url));
=> http://example2.com

$piece = substr($url, strpos($url, 'param2=') + 7 , +count($url));
=> h

$piece = substr($url, strpos($url, 'param2=') + 7 , -(count($url)+1));
=> http://example2.co

$piece = substr($url, strpos($url, 'param2=') + 7 , -(count($url)-1));
=>        (empty)

$piece = substr($url, strpos($url, 'param2=') + 7 , -1);
=> http://example2.com

$piece = substr($url, strpos($url, 'param2=') + 7 , -0);
=>        (empty)

So I never get the last char, maybe you know what I am doing wrong.

http://example2.com/ , the '/' is always cut off. Also tried without / but then is the m missing instead. — nova, Oct 07 '16 at 12:17
See the Dup and lookup [`parse_url()` in the manual](http://php.net/manual/en/function.parse-url.php) — RiggsFolly, Oct 07 '16 at 12:18
either use `parse_url();` or `explode('&param2=',$string)[1]` — Alive to die - Anant, Oct 07 '16 at 12:19
parse_url() is no option for me because it automatically decodes the params. — nova, Oct 07 '16 at 12:20
You do know that simply omitting the third parameter to `substr()` gives you the rest of the string? See [example](https://eval.in/657099) Docs state: _If length is omitted, the substring starting from start until the end of the string will be returned._ — syck, Oct 07 '16 at 12:23

Alive to die - Anant · Accepted Answer · 2016-10-07T12:30:51.483

2

You can use explode():-

<?php

$string = 'http://example.de/?param=1&param2=http://example2.com/';

echo explode('&param2=',$string)[1];

Output:-https://eval.in/657097

For your query in comment, do like below:-

https://eval.in/657101

edited Oct 07 '16 at 12:30

answered Oct 07 '16 at 12:22

Alive to die - Anant

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Only problem with this is if in the case that there are multiple parameters after _param2_ – Allen Butler Oct 07 '16 at 12:25
I'd explode a second time on _&_ and call with index _0_ – Allen Butler Oct 07 '16 at 12:29
@AllenButler check my second example link in my answer. Glad to help you. cheers :):) – Alive to die - Anant Oct 07 '16 at 12:46
@Anant `parse_url()` should be used here – hek2mgl Oct 27 '16 at 12:03

how to NOT cut off the last char with substr?

1 Answers1