Initialize member of the struct

Question

In C, I'm trying to initialise a structure's member but I'm unable to do it. Here is my code construct:

struct values{
  int a;
  int b;
  int b;
  int d;
 };
struct values value[65535];

I want to initialise b member of the structure to -1 for all the values in the struct object array. I'm unable to figure out good way to do this.

Which compiler are you using? GCC has an non-standard extension that makes it easy; Clang probably supports it too for GCC compatibility. Otherwise, there isn't an easy way to do it. — Jonathan Leffler, Oct 09 '16 at 02:40

score 0 · Answer 1 · answered Oct 09 '16 at 02:43

0

How about:

for (i = 0; i < 65535; i++)
    value[i].b = -1;

answered Oct 09 '16 at 02:43

ad absurdum

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score 0 · Answer 2 · answered Oct 09 '16 at 02:43

0

#include<stdio.h>
struct values{
  int a;
  int b=-1;
  int c;
  int d;
 };
struct values value[65535];
int main(){
    printf("%d",value[2].b);
    return 0;
}

Tell me if this helps.

answered Oct 09 '16 at 02:43

red5pider

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Which language is this code for? Or, if you think it is C, which compiler? – Jonathan Leffler Oct 09 '16 at 02:43
Question is asked in c – red5pider Oct 09 '16 at 02:47
Yes, but the code you show is not valid C — that's why I asked which language or which compiler. – Jonathan Leffler Oct 09 '16 at 02:47
compiler TDM-GCC 4.9.2 64-bit – red5pider Oct 09 '16 at 02:48
I don't know the significance of the `TDM` prefix, but standard GCC 6.2.0 (and 4.9.1) rejects it: `error: expected ‘:’, ‘,’, ‘;’, ‘}’ or ‘__attribute__’ before ‘=’ token` and identifies `int b=-1;` as the code that causes the error. That's compiling with no options specified to make it compile more stringently. – Jonathan Leffler Oct 09 '16 at 02:50

Initialize member of the struct

2 Answers2